Codefights

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Regular Months

Description

In an effort to be more innovative, your boss introduced a strange new tradition: the first day of every month you’re allowed to work from home. You like this rule when the day falls on a Monday, because any excuse to skip rush hour traffic is great!

You and your colleagues have started calling these months regular months. Since you’re a fan of working from home, you decide to find out how far away the nearest regular month is, given that the currMonth has just started.

For your convenience, here is a list of month lengths (from January to December, respectively):

  • Month lengths: 31, 28, 31, 30, 31, 30, 31, 31, 30, 31, 30, 31.

Please, note that in leap years February has 29 days.

Note (leap years): Year is leap if its number is divisible by 4 and isn’t divisible by 100 or if its number is divisible by 400.

Example

For currMonth = "02-2016", the output should be regularMonths(currMonth) = "08-2016".

February of 2016 year is regular, but it doesn’t count since it has started already, so the next regular month is August of 2016 - which is the answer.

Input/Output

  • [execution time limit] 4 seconds (js)

  • [input] string currMonth

    A string representing the current month in the format mm-yyyy, where mm is the number of the month (1-based, i.e. 01 for January, 02 for February and so on) and yyyy is the year.

    Guaranteed constraints:
    1 ≤ int(mm) ≤ 12
    , 1970 ≤ int(yyyy) ≤ 2100.

  • [output] string

    • The earliest regular month after the given one in the same format as currMonth.

[JavaScript (ES6)] Syntax Tips

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// Prints help message to the console
// Returns a string
function helloWorld(name) {
console.log("This prints to the console when you Run Tests");
return "Hello, " + name;
}

Solution

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function regularMonths(currMonth) {
  currMonth = currMonth.split("-").join("-01-");
  var date = new Date();
  date.setTime(Date.parse(currMonth));
  date.setMonth(date.getMonth() + 1);
  while (date.getDay() !== 1) {
    date.setMonth(date.getMonth() + 1);
  }

  return `${("0" + (date.getMonth() + 1)).substr(-2)}-${date.getFullYear()}`;
}