Spiral Numbers
Description
Construct a square matrix with a size N × N containing integers from 1 to N * N in a spiral order, starting from top-left and in clockwise direction.
Example
For n = 3, the output should be
spiralNumbers(n) = [[1, 2, 3],
[8, 9, 4],
[7, 6, 5]]Input/Output
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[execution time limit] 4 seconds (js)
-
[input] integer n
Matrix size, a positive integer.
Guaranteed constraints:
3 ≤ n ≤ 100.
- [output] array.array.integer
[JavaScript (ES6)] Syntax Tips
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// Prints help message to the console
// Returns a string
function helloWorld(name) {
console.log("This prints to the console when you Run Tests");
return "Hello, " + name;
}
Solution
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function spiralNumbers(n) {
var res = Array(n*n).fill(null).map((el,i)=>i+1);
var m = [];
var i = 0;
while(res.length) {
m.reverse();
m = m.length?m[0].map((col, i) => m.map(row => row[i])) : m;
m.unshift(res.splice(-(Math.floor(i/2)+1)));
i++;
}
return m;
}