Legs Count
Description
Implement the missing code, denoted by ellipses. You may not modify the pre-existing code.
You really love counting stuff. In fact, right now you’re sitting on a meadow and counting all the legs you see there! There are some people, some dogs, and some cats on the meadow. You’re pretty confident that each human has 2
legs and that cats and dogs have 4
legs each.
The information about all the creatures on the meadow is stored in the table creatures. It has the following structure:
- id: The unique creature ID;
- name: The creature’s name;
- type: The creature’s type -
"human"
,"cat"
, or"dog"
. This column hasENUM
type.
You want to calculate the total number of legs in the meadow. Given the table creatures, build a new table that only contains one column summary_legs
and has only one row with the total number of legs that you can see.
Example
For the following table creatures
id | name | type |
---|---|---|
1 | Mike | human |
2 | Misty | cat |
3 | Max | dog |
4 | Tiger | human |
the output should be
summary_legs |
---|
12 |
There are 2
humans, 1
cat, and 1
dog, so there are 2 _ 2 + 1 _ 4 + 1 \* 4 = 12
legs in total.
- [execution time limit] 10 seconds (mysql)
Solution
1
2
3
4
5
DROP PROCEDURE IF EXISTS legsCount;
CREATE PROCEDURE legsCount()
SELECT SUM(IF(type='human',2,4)) as summary_legs
FROM creatures
ORDER BY id;